Finding The X-intercepts Of Y=6tan(x/2)-3 Graphing Calculator Estimation

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What are the x-intercepts of the function y=6tan(x/2)-3? Estimate the answer using a graphing calculator.

Introduction to xx-Intercepts and Trigonometric Functions

In mathematics, finding the xx-intercepts of a function is a fundamental task. The xx-intercepts are the points where the graph of the function intersects the xx-axis. At these points, the yy-coordinate is zero. Understanding xx-intercepts is crucial for analyzing the behavior of functions, particularly in fields like calculus, physics, and engineering. For trigonometric functions, finding these intercepts can reveal periodic behavior and critical points, which are essential in modeling cyclical phenomena. The tangent function, specifically, exhibits interesting properties due to its periodicity and asymptotes, making the determination of its xx-intercepts a significant analytical exercise.

When dealing with trigonometric functions such as the tangent function, the xx-intercepts often occur at regular intervals due to the periodic nature of these functions. This periodicity means the function repeats its values over consistent intervals, leading to a series of xx-intercepts rather than just a single point. The tangent function, denoted as tan(x)\tan(x), has a period of π\pi, which means its values repeat every π\pi units along the xx-axis. This characteristic periodicity is crucial when determining the general form of the xx-intercepts.

Furthermore, transformations applied to the tangent function, such as horizontal stretches or shifts, can affect the location and spacing of these intercepts. For example, in the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3, the argument x2\frac{x}{2} inside the tangent function indicates a horizontal stretch, which alters the period of the function. The constant term 3-3 represents a vertical shift, which can also influence the xx-intercepts by changing the vertical position of the graph. To accurately find the xx-intercepts, one must account for these transformations and their effects on the function's behavior.

In this article, we delve into the process of finding the xx-intercepts for the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3. We will employ both algebraic methods and graphical estimation using a calculator to arrive at the solution. This approach will not only provide the specific xx-intercepts but also enhance our understanding of how transformations impact the behavior of trigonometric functions. By the end of this discussion, you will have a clear methodology for solving similar problems and a deeper appreciation for the interplay between algebra and graphical analysis in mathematics.

Algebraic Approach to Finding xx-Intercepts

To find the xx-intercepts of the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3, we need to solve the equation 6tan(x2)3=06\tan(\frac{x}{2}) - 3 = 0. This algebraic manipulation will lead us to the values of xx where the function crosses the xx-axis. The process involves isolating the trigonometric function and then finding the angles that satisfy the resulting equation. Each step is crucial in ensuring we correctly identify the points where the function's value is zero.

First, let's isolate the tangent function. We start by adding 3 to both sides of the equation:

6tan(x2)=36\tan(\frac{x}{2}) = 3

Next, we divide both sides by 6:

tan(x2)=36=12\tan(\frac{x}{2}) = \frac{3}{6} = \frac{1}{2}

Now we have the equation tan(x2)=12\tan(\frac{x}{2}) = \frac{1}{2}. To solve for xx, we need to find the angle whose tangent is 12\frac{1}{2}. We can use the inverse tangent function, also known as arctangent, to find this angle. The arctangent function, denoted as arctan\arctan or tan1\tan^{-1}, gives us the angle whose tangent is a given value. Applying the arctangent to both sides, we get:

x2=arctan(12)\frac{x}{2} = \arctan(\frac{1}{2})

Using a calculator, we find that:

arctan(12)0.4636\arctan(\frac{1}{2}) \approx 0.4636 radians

This gives us one solution for x2\frac{x}{2}. However, since the tangent function is periodic with a period of π\pi, there are infinitely many solutions. The general solution for x2\frac{x}{2} can be written as:

x2=0.4636+nπ\frac{x}{2} = 0.4636 + n\pi, where nn is any integer.

To solve for xx, we multiply both sides by 2:

x=2(0.4636+nπ)=0.9272+2nπx = 2(0.4636 + n\pi) = 0.9272 + 2n\pi, where nn is any integer.

Thus, the xx-intercepts of the function are given by x=0.9272+2nπx = 0.9272 + 2n\pi, where nn is any integer. This algebraic approach allows us to precisely determine the xx-intercepts by solving the equation derived from setting the function equal to zero and using the properties of the tangent function and its inverse.

Graphical Estimation Using a Calculator

To estimate the xx-intercepts of the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3 using a graphing calculator, we need to input the function and analyze its graph. Graphing calculators provide a visual representation of functions, allowing us to identify where the graph crosses the xx-axis. This method complements the algebraic approach by offering a visual confirmation and a means to estimate solutions when algebraic methods might be more complex or time-consuming. The process involves setting up the calculator, inputting the function, adjusting the viewing window, and identifying the intercepts.

First, turn on your graphing calculator and navigate to the equation editor (usually denoted as “Y=” on most calculators). Input the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3. Make sure your calculator is set to radian mode, as this is the standard unit for trigonometric functions in mathematical contexts. Setting the correct mode is crucial for obtaining accurate results, as degree mode would yield different values due to the different scales used for angles.

Next, adjust the viewing window to an appropriate range. Since the tangent function has asymptotes and a period, choosing a suitable window is essential for observing the behavior of the graph. A typical window might range from 2π-2\pi to 2π2\pi for xx and from 10-10 to 1010 for yy. These ranges allow you to see at least one full period of the function and observe its key features, such as intercepts and asymptotes. You can adjust these ranges based on the specific behavior you want to examine more closely.

Once the function is graphed, use the calculator’s built-in features to find the xx-intercepts. Most graphing calculators have a “zero” or “root” function under the “CALC” menu (usually accessed by pressing the “2nd” key followed by the “TRACE” key). This function prompts you to select a left bound, a right bound, and a guess near the intercept you want to find. The calculator then uses numerical methods to find the xx-value where the function equals zero within the specified interval.

By using the calculator's zero-finding function, we can estimate the first positive xx-intercept to be approximately 0.92730.9273. Since the period of the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3 is 2π2\pi (due to the x2\frac{x}{2} inside the tangent function), the xx-intercepts repeat every 2π2\pi units. Therefore, the general form of the xx-intercepts can be expressed as 0.9273+2nπ0.9273 + 2n\pi, where nn is any integer. This result aligns with the algebraic solution we obtained earlier.

Comparing and Verifying the Solutions

Comparing the algebraic and graphical solutions is a crucial step in verifying the accuracy of our results for the xx-intercepts of the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3. Both methods, algebraic manipulation and graphical estimation using a calculator, provide insights into the function's behavior, and any discrepancies between the solutions should prompt a closer examination of the steps taken. The consistency between the two approaches enhances our confidence in the correctness of the solution and reinforces our understanding of the function.

From the algebraic approach, we found the xx-intercepts to be x=0.9272+2nπx = 0.9272 + 2n\pi, where nn is any integer. This solution was derived by setting the function equal to zero, isolating the tangent function, and using the arctangent to find the principal value. The periodicity of the tangent function was then considered to express the general solution for all xx-intercepts. This method provides a precise, symbolic representation of the intercepts, allowing us to calculate specific values for any integer nn.

Graphically, we used a calculator to plot the function and identify the xx-intercepts. The calculator's zero-finding function gave us an estimated value of approximately 0.92730.9273 for the first positive xx-intercept. Recognizing that the period of the function is 2π2\pi, we expressed the general solution as 0.9273+2nπ0.9273 + 2n\pi, where nn is any integer. This graphical estimation offers a visual confirmation of the algebraic solution, showing the points where the graph crosses the xx-axis.

When we compare the two solutions, we observe a high degree of consistency. The algebraic solution of 0.9272+2nπ0.9272 + 2n\pi is very close to the graphical estimate of 0.9273+2nπ0.9273 + 2n\pi. The slight difference can be attributed to the calculator's numerical approximation in the graphical method. This close agreement between the two methods validates our approach and increases our confidence in the accuracy of the result.

To further verify the solutions, we can substitute specific values of nn into the general solution and check if the resulting xx-values indeed make the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3 equal to zero. For example, if we let n=0n = 0, we get x0.9272x \approx 0.9272. Plugging this value into the function:

y=6tan(0.92722)36tan(0.4636)36(0.5)3=0y = 6\tan(\frac{0.9272}{2}) - 3 \approx 6\tan(0.4636) - 3 \approx 6(0.5) - 3 = 0

This confirms that 0.92720.9272 is indeed an xx-intercept. We can perform similar checks for other values of nn to further validate the general solution. The congruence between algebraic solutions and graphical estimations, coupled with numerical verification, provides a robust confirmation of the xx-intercepts for the given function.

Conclusion

In conclusion, we have successfully found the xx-intercepts of the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3 using both algebraic and graphical methods. The algebraic approach involved setting the function equal to zero, isolating the tangent function, and using the arctangent to solve for xx. This yielded the general solution x=0.9272+2nπx = 0.9272 + 2n\pi, where nn is any integer. The graphical method utilized a graphing calculator to visualize the function and estimate the xx-intercepts, resulting in a solution of 0.9273+2nπ0.9273 + 2n\pi, where nn is any integer. The close agreement between these two methods underscores the accuracy of our findings.

The process of finding xx-intercepts is a fundamental concept in mathematics, crucial for understanding the behavior of functions. By employing both algebraic and graphical techniques, we can gain a more comprehensive understanding and verify our solutions. The algebraic method provides a precise, symbolic representation, while the graphical method offers a visual confirmation, making complex problems more accessible.

Understanding the periodic nature of trigonometric functions, such as the tangent function, is essential for determining the general form of the xx-intercepts. The period of the tangent function is π\pi, but transformations, such as the x2\frac{x}{2} in our function, can alter the period. In this case, the period of y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3 is 2π2\pi, which is reflected in the general solution for the xx-intercepts.

Furthermore, this exercise highlights the importance of using technology, such as graphing calculators, to complement algebraic methods. Graphing calculators provide a powerful tool for visualizing functions and estimating solutions, especially in cases where algebraic solutions may be challenging to obtain. However, it is equally important to understand the underlying algebraic principles to ensure accurate interpretation of the graphical results.

In summary, the xx-intercepts of the function y=6tan(x2)3y = 6\tan(\frac{x}{2}) - 3 are given by (0.9273+2nπ,0)(0.9273 + 2n\pi, 0), where nn is any integer. This result was consistently obtained through both algebraic and graphical methods, reinforcing the importance of a multifaceted approach to problem-solving in mathematics. The ability to find xx-intercepts is a valuable skill that extends to various mathematical and scientific applications, making it a core concept in the study of functions and their behaviors.